Answer:
a. u = 21. 50 m/s
Maximum height from the base of the cliff = 32 + 23.56 = 55.56 m
Step-by-step explanation:
mass of rock = 0.26 kg
Height = 32 m (the cliff cannot be 32 mm it should be 32 m)
initial velocity (u) = ?
final velocity(v) = 33 m/s
Initial mechanical energy is equal to final mechanical energy. The object undergoes potential and kinetic energy.
initial mechanical energy = final mechanical energy
mgh + 1/2mu² = mgh + 1/2mv²
mgh + 1/2mu² = 0 + 1/2mv²
u² = v² -2gh
u = √v² -2gh
u = √1089 - 2 × 9.81 × 32
u = √1089 - 627.84
u = √461.16
u = 21.4746362018
u = 21. 50 m/s
b .The greatest maximum height
1/2 mu² = mgh
1/2u² = gh
h = u²/2g
h = (21.50)²/2 × 9.81
h = 462.25 /19.62
h = 23.5601427115 m
Maximum height from the base of the cliff = 32 + 23.56 = 55.56 m