Question

HCF 128, 192, and 80?​

Answer 1

16

Explanation:

Express each number as a product of it's prime factors

128 =
`2^(7)`

192 =
`2^(6)` × 3

80 =
`2^(4)` × 5

Identify those prime factors that the numbers have in common and multiply them.

The common factor of all 3 numbers is
`2^(4)`

HCF =
`2^(4)` = 16

Answer 2

HCF = 2 × 2 × 2 × 2

= 16

Explanation:

2 128 192 80

2 64 96 40

2 32 48 20

2 16 24 10

8 12 5

At this stage there is no common factor for the three numbers

HCF = 2 × 2 × 2 × 2

= 16