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1 vote
Trigonometry
Trigonometric Equations
0 ≤ x ≤ 2 π , solve the equation: sin 2x=√ 3/2

User Edis
by
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2 Answers

4 votes

Answer:

x = π/6, π/3, 7π/6, 4π/3

Explanation:

sin 2x = √3/2

basic angle = π/3

2x = π/3,

π - π/3 = 2π/3,

π/3 + 2π = 7π/3,

2π/3 + 2π = 8π/3

x = π/6, π/3, 7π/6, 4π/3

User Elia Schenker
by
8.1k points
2 votes
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Trigonometry Trigonometric Equations 0 ≤ x ≤ 2 π , solve the equation: sin 2x=√ 3/2-example-1
User Nanda Z
by
7.4k points

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