Answer:
0.2 mL
Step-by-step explanation:
When an acid and a base react, they converge in a neutralization reaction. So the formed products are water and a salt. The equation is:
H₂SO₄ (aq) + 2 NaOH (aq) → Na₂SO₄(aq) + 2H₂O(l)
1 mol of sulfuric needs 2 moles of hydroxide to react.
Let's find out the moles of base:
Molarity = mol/ volume (L) → molarity . volume(L) = moles
We make the conversion → 20 mL . 1L /1000mL = 0.020L
0.001 M . 0.020L = 2×10⁻⁵ moles
So the rule of three is: 2 moles of base react with 1 mol of sulfuric
Therefore 2×10⁻⁵ moles of base will react with (2×10⁻⁵ . 1) / 2 = 1×10⁻⁵ moles of acid. Let's find out the volume:
Molarity = mol /volume(L) → mol / Molarity = Volume(L)
1×10⁻⁵ mol / 0.05 M = 2×10⁻⁴ L.
If we want the value in mL, we make the conversion:
2×10⁻⁴ L . 1000 mL /1L = 0.2 mL