Question

How many milligrams of CO exist in 12000 liters of air with 10 ppm of CO?

1.2 × 10^4
12 × 10^3
12 × 10^5
12 × 10^4

Answer 1

There are approximately 537.6 milligrams of CO in 12000 liters of air with 10 ppm of CO.

Step-by-step explanation:

To calculate the amount of CO in 12000 liters of air with 10 ppm of CO, we can use the mass concentration of CO₂ in air. The mass concentration of CO₂ in air is 1.6 ppm. Since CO and CO₂ have the same molar mass, we can assume that the mass concentration of CO is also 1.6 ppm.

To calculate the milligrams of CO in the given volume of air, we can use the formula:

Milligrams of CO = (mass concentration of CO x volume of air x molar mass of CO) / 1000

Plugging in the values, we get:

Milligrams of CO = (1.6 ppm x 12000 L x 28.01 g/mol) / 1000 = 537.6 mg

Therefore, there are approximately 537.6 milligrams of CO in 12000 liters of air with 10 ppm of CO.

Answer 2

The mass of CO in 12,000 Liters of air is
`12* 10^4 mg`.

Step-by-step explanation:

The ppm is the amount of solute (in milligrams) present in one Liter of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

`\text{ppm}=\frac{\text{Mass of solute}(mg)}{\text{Volume of solution}(L)}`

The ppm concentration of CO = 10 ppm

Mass of CO = m

Volume of air = 12,000 L

`10 =(m)/(12,000 L)`

`m=10* 12,000 mg=120,000 mg=12* 10^4 mg`

The mass of CO in 12,000 Liters of air is
`12* 10^4 mg`.