Question

Calculate the [OH−]

[H3O+]=3.0×10−9M

Answer 1

Thus the value of [OH⁻] calculated is = 3.3 × 10⁻⁶ M

Step-by-step explanation:

Given:

Concentration of H₃O⁺ = 3.3 × 10⁻⁹ M

To Find:

Concentration of OH⁻ ion = ?

Solution:

From the
`K_(w)` value, and the concentration of H⁺ ion, we can find the concentration of hydroxyl ions, as
`K_(w)` is the product of the concentration of H⁺ and OH⁻ ions. We have the concentration of hydronium ion or H⁺ ion and
`K_(w)` value, dividing
`K_(w)` by the H⁺ ion concentration, we will get the concentration of OH⁻ ion as,

`K_(w)` = [H₃O⁺] × [OH⁻]

= 3.0 × 10⁻⁹ × [OH⁻]

Now we have to divide as,

[OH⁻] =
`$(1*10^-14)/(3*10^(-9))` = 3.3 × 10⁻⁶ M