Question

4. The 50-kg crate shown in Fig. rests on a horizontal surface for which the coefficient of

kinetic friction is u - 0.3. If the crate is subjected to a 400-N towing force as shown,
determine the acceleration of the crate.
your
P = 400 N
490.5 N
400 N
too

30
30°
+
F-0.3 Nc
Nc
ΣΕ = max
Σ F, = may
A. a = 4. 185 m/s2
B. a = 5. 185 m/s2
C. a = 6. 185 m/s2
D. The entire above are false

Answer 1

5.057 m/s^2

Step-by-step explanation:

Force of kinetic friction = .3 = F /normal force

.3 = F /(50* 9.81) F of friction = 147.15

Net force = 400 - 147.5 = 252.85 N

F = m * a

252.85 = 50 * a a = 5.057 m/s^2