Answer:
Mass = 36.4 ×10⁻³ g
Step-by-step explanation:
Given data:
Volume of container = 100 mL ( 100/1000 = 0.1 L)
Pressure = 688 mmHg (0.9 atm)
Temperature = 565°C ( 565 + 273 = 838 K)
Mass in grams of nitrogen = ?
Solution:
According to ideal gas equation,
PV = nRT
n = number of moles
P = pressure
R = general gas constant
T = temperature
From this equation we will determine the number of moles and then we we will calculate the mass.
n = PV/RT
n = 0.9 atm × 0.1 L / 0.0821 atm. L / mol.K × 838 K
n = 0.09 / 68.8
n = 0.0013 mol
or
n = 1.3×10⁻³ mol
Mass of nitrogen gas:
Mass = number of moles × molar mass
Mass = 1.3×10⁻³ mol × 28 g/mol
Mass = 36.4 ×10⁻³ g