Question

A runner starts from rest and accelerates uniformly to a speed of 8.0 meters per

second in 4.0 seconds. The magnitude of the acceleration of the runner is
O
32 m/s/s
o
9.8 m/s/s
O
2.0 m/s/s
O 0.50 m/s/s

Answer 1

2m/s2

Step-by-step explanation:

a = v - u /t

Since the runner starts from rest, initial velocity u is Zero

Final velocity v = 8.0m/s

Time = 4.0secs

a = 8.0 - 0 /4.0

a = 8.0/4.0

a = 2m/s2

Answer 2

Magnitude of acceleration is 2 m/s²

Step-by-step explanation:

• Here, the speed or velocity of the runner = 8 m/s and time = 4 s. Using these values, the magnitude of the acceleration has to be found.
• Acceleration is given by a = velocity/time

⇒ Acceleration = 8/4 = 2 m/s²

So the magnitude of acceleration is 2 m/s²