Question

Arunner starts from rest and accelerates uniformly to a speed of 8.0 meters per

second in 4.0 seconds. The magnitude of the acceleration of the runner is
O 32 m/s/s
O 9.8 m/s/s
O 2.0 m/s/s
O
0.50 m/s/s

Answer 1

2.0 m/s/s

Step-by-step explanation:

The acceleration of an object is the rate of change of velocity of the object.

Mathematically, it is given by:

`a=(v-u)/(t)`

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

Acceleration is a vector, so it has both a magnitude and a direction.

For the runner in this problem, we have:

u = 0 is the initial velocity (he starts from rest)

v = 8.0 m/s is the final velocity

t = 4.0 s is the time taken

Substituting, we find

`a=(8.0-0)/(4.0)=2.0 m/s^2`