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Suppose you deposit $1200 into a savings account that compounds interest continuously at 3.9%. You left your money in the account to grow for 10 years. How much money did you have in the account at the end of the ten year time period?

1 Answer

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Answer: you would have $1772 at the end of 10 years.

Explanation:

The formula for continuously compounded interest is

A = P x e (r x t)

Where

A represents the future value of the investment after t years.

P represents the present value or initial amount invested

r represents the interest rate

t represents the time in years for which the investment was made.

e is the mathematical constant approximated as 2.7183.

From the information given,

P = $1200

r = 3.9% = 3.9/100 = 0.039

t = 10 years

Therefore,

A = 1200 x 2.7183^(0.039 x 10)

A = 1200 x 2.7183^(0.39)

A = $1772 to the nearest dollar

User Slobodan Kovacevic
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