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What is the pH of a solution that has a [H+]=1.75x10^-11
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What is the pH of a solution that has a [H+]=1.75x10^-11

User Jruz
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pH = - \log[\text{H}^(+)] = -\log \left(1.75 * 10^(-11) \right) = 10.757

User Samir Hinojosa
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