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For the function f (x) = x^2 - 2x - 8, find the two points x when f (x) =7
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For the function f (x) = x^2 - 2x - 8, find the two points x when f (x) =7

User Alperefesahin
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3.5k points

1 Answer

6 votes

Explanation:


{x}^(2) - 2x - 8 = 7


{x}^(2) - 2x - 8 - 7 = 0


{x}^(2) - 2x - 15 = 0


{x}^(2) - 5x + 3x - 15 = 0


x(x - 5) + 3(x - 5) = 0


(x - 5)(x + 3) = 0


x = 5 \: \: or \: \: x = - 3

User Steve Wranovsky
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3.0k points
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