Answer:
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Explanation:
Suppose that you are looking for b, instead of the irrelevant value of m
The statements of this problem suggest us to look for the Least Common Multiple (LCM) of 30, 36 and 45
The number b will be that LCM + 7.
Hence,
30 = 2 x 3 x 5
36 = 2^2 x 3^2
45 = 3^2 x 5
LCM = 180
Therefore the smallest possible value of b (or ‘m’ as per question) is -> LCM+7 that is 180+7= 187