Answer:
∠I ≈ 53.13°
Explanation:
It can be seen from the figure that IP is perpendicular to KP
=> So that IPK is the right-angled triangle with angel IPK equal to 90°
In a right-angled triangle, there is a formula as following:
+) sin of an acute angel = length of opposite side/ length of hypotenuse
In triangle IPK, ∠I is an acute angel, its opposite side is KP.
The hypotenuse of triangle IPK is IK
So that, we have:
+) sin ∠I = KP/ IK = 8/10 = 0.8
=> ∠I ≈ 53.13°