THE INITIAL VALUE IN THE FUNCTION ARE X=0 AND Y=2 OR X=3 AND Y=0.
Explanation:
The initial value of the line segment is the value at which X=0 .
X=0 means nothing but a Y-intercept.
Now set X=0, in the function 2x+3y=6
2(0)+3y=6.
3y=6.
Therefore Y=2
so (0,2) is one point on the graph or line segment.
similarly considering X=3 in the line segment and that means Y=0.
Y=0 indicates X-intercept.
substituting X=3 in the function
2(X)+3(0)=6
2X=6
Therefore X=3
so (3,0) is another point on the line segment or graph.