Answer:
Explanation:
Recall that the formula for the area of a rectangle of length L and width W is
A = LW.
What if the area is 19 cm^2 and the length is 38 cm? Solving the above equation for W, we get
W = A/L
and if we let A = 19 cm^2 and L = 38 cm, then W would be W = (19 cm^2) ? (38 cm) = (1/2) cm. The rectangle would be very narrow, but certainly possible.