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An envelope measures 5 inches by 12 inches. A pencil is placed in the envelope at a diagonal. What is the maximum possible lenght of the pencil?

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the maximum possible length of the pencil is 13 inches

Explanation:

Here we have , An envelope measures 5 inches by 12 inches. A pencil is placed in the envelope at a diagonal. We need to find What is the maximum possible length of the pencil . Let's find out:

We know that maximum length which can be fitted in envelope will be the length of diagonal of envelope . So

By Pythagoras theorem


Diagonal^2 = length^2 +breadth^2


Diagonal^2 = length^2 +breadth^2


Diagonal^2 =5^2 +12^2


Diagonal^2 =25 +144


Diagonal^2 = 169


√(Diagonal^2) = √(169)


Diagonal= 13 inch

Therefore, the maximum possible length of the pencil is 13 inches .

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