Question

When 24.68 grams of lithium nitrate (LiNO3) are produced, how many moles of lithium chloride (LiCI) reacted ?

Answer 1

0.3 moles of lithium chloride (LiCI) reacted to produce 24.68 grams of lithium nitrate (LiNO3).

Step-by-step explanation:

Balanced equation for the reaction is:

2LiCl + Pb(NO3)2 ⇒2 LiNO3 + PbCl2

Data given:

mass of LiNO3 produced = 24.68 grams

moles of LiCl reacted= ?

atomic mass of 1 mole of LiNO3 = 68.946 Grams

Number of moles =
`(mass)/(atomic mass of one mole)`

putting the values in the above equation:

`(24.68)/(68.946)`

= 0.3 moles

from the reaction,

2 moles of LiCl reacted to form 2 moles of LiNO3

so, x moles of LiCl reacted to form 0.3 moles of LiNO3

`(2)/(2)` =
`(0.3)/(x)`

x = 0.3 moles of LiCl will react to form 0.3 moles of LiNO3.