The electric current passing through the bulb would be 3.3A
Step-by-step explanation:
Given:
Electric charge, q = 800C
Time, t = 4 min
= 4 X 60 sec
= 240 sec
Electric current, I = ?
We know,
![Current = (Charge)/(Time)](https://img.qammunity.org/2021/formulas/physics/middle-school/zrp7xfognk5hcteeeesc18apu2z9ffz872.png)
On substituting the value we get:
![I = (800)/(4 X 60) \\\\I = 3.3A](https://img.qammunity.org/2021/formulas/physics/middle-school/wolo2wglblrliw8twwkkvbn0yiwoyuowzk.png)
Thus, the electric current passing through the bulb would be 3.3A