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Can someone help me please

Can someone help me please-example-1
User Bnqtoan
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Question # 1

Answer:

The surface area of the square pyramid is 44.84.

Explanation:

As the perpendicular height = 3

square base side = 4

Using the formula to compute the surface area of the square pyramid:


A=a^2+2a\sqrt{(a^2)/(4)+h^2}

Here:

a = Base Edge = 4

h = height = 3


A=4^2+2\left(4\right)\sqrt{(4^2)/(4)+3^2}


\mathrm{Remove\:parentheses}:\quad \left(a\right)=a


A=4^2+2\cdot \:4\sqrt{(4^2)/(4)+3^2}


A=4^2+8√(13)
2\cdot \:4\sqrt{(4^2)/(4)+3^2}=8√(13)


A=16+8√(13)


A=44.84

Therefore, the surface area of the square pyramid is 44.84.

Question # 2

Answer:

The surface area of a cube is 37.5

Explanation:

Given the the length of one of the sides = s = 2.5

To find the surface area of a cube, using the formula


A=\:6s^2


A=\:6\left(2.5\right)^2


A=6\cdot \:6.25
2.5^2=6.25


A=37.5

Therefore, the surface area of a cube is 37.5

User Yinglin
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