Question

Let f(x)=x2+15x+56

What are the zeros of the function?

Enter your answers in the boxes

and

Answer 1

-7 , -8

Explanation:

x² + 15x + 56 = 0

x² + 7x + 8x + 56 = 0

x(x + 7) + 8(x + 7) = 0

(x + 7)(x + 8) = 0

x = -7 , -8

Answer 2

-8, -7

Explanation:

f(x)=x^2+15x+56

0 =x^2+15x+56

What two numbers multiply together to make 56 and add together to 15

7*8 = 56

7+8=15

0 = (x+8) (x+7)

Then use the zero product property

x+8 =0 x+7 =0

x+8-8 =0-8 x+7-7 =0-7

x=-8 x=-7