Answer:
A)2100 ml
Explanation:
Given total vinegar is 3 1/2 liters and the used vinegar is 3/5 of the vinegar in the beaker:
#First calculate the amount of vinegar not poured in the beaker:
![V_o=V_t-V_b\\\\=3(1)/(2)(1-(2)/(3))\\\\=1(1)/(6)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/p3ejyddo2azw1t397cq8be2kpudqbn5hrn.png)
#Calculate amount of vinegar used in experiment:
![V_b=(2)/(3)V_t=(2)/(3)(3(1)/(2))=2(1)/(3)\\\\V_u=(3)/(5)V_b=(3)/(5)* 2(1)/(3)=1(2)/(5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4d7rrvm1itr9fa5wcs24xnw9a3to72h6c2.png)
#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:
![V_r=V_t-V_u\\\\=3(1)/(2)-1\frac{2}5}\\\\=2(1)/(10)* 1000\ ml\\\\=2100\ ml](https://img.qammunity.org/2021/formulas/mathematics/middle-school/h6kg9h4um83uwavy0s7u99jj4zz2c9a4iu.png)
Hence, the unused vinegar is 2100 ml