Question

Joseph is driving at an average of 50 miles per hour on a 330-mile road trip. On the way back, Joseph was about to average 60 miles per hour. How much faster was the trip back home

Answer 1

1 second faster was the trip back home .

Explanation:

Here we have , Joseph is driving at an average of 50 miles per hour on a 330-mile road trip. On the way back, Joseph was about to average 60 miles per hour. We need to find How much faster was the trip back home . Let's find out:

• Joseph is driving at an average of 50 miles per hour on a 330-mile road trip.

We know that ,
`Speed = (Distance)/(time)`

⇒
`Speed = (Distance)/(time)`

⇒
`50 = (330)/(time)`

⇒
`time = (330)/(50)`

⇒
`time = 6.6.sec`

• On the way back, Joseph was about to average 60 miles per hour.

We know that ,
`Speed = (Distance)/(time)`

⇒
`Speed = (Distance)/(time)`

⇒
`60 = (330)/(time)`

⇒
`time = (330)/(60)`

⇒
`time = 5.5sec`

So, Time difference in both trips is
`6.5sec-5.5sec=1sec` .

Therefore, 1 second faster was the trip back home .