Question

A gas at 400 k is placed in a 4.0 l moveable piston. The gas is cooled to 252 k. What is the new volume of the piston?

Answer 1

2.52L

Step-by-step explanation:

Given parameters:

T₁ = 400K

V₁ = 4L

T₂ = 252K

unknown

V₂ = ?

Solution:

To solve this problem, we are going to apply charle's law. The law states that the volume of a fixed mass of gas is directly proportional to temperature provided pressure is constant.

Mathematically,

`(V_(1) )/(T_(1) ) = (V_(2) )/(T_(2) )`

Substitute and solve for V₂

`(4)/(400) = (V_(2) )/(252)`

V₂ = 2.52L