Question

What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)?

3
y=-3x+33

Answer 1

y = 4x + 16

Explanation:

We are asked to find the equation of a line parallel to

y - 1 = 4(x + 3)

Step 1 : find the slope

y - 1 = 4(x + 3)

Open the bracket with 4

y - 1 = 4x + 12

making y the subject of the formula

y = 4x + 12 + 1

y = 4x + 13

Slope m = 4

Step 2 : substitute m into the equation

y - y_1 = m( x - x_1)

y - y_1 = 4(x - x_1)

Step 3: substitute the point into the equation

( 4 , 32)

x_1 = 4

y_1 = 32

y - y_1 = 4( x - x_1)

y - 32 = 4(x - 4)

Open the bracket with 4

y - 32 = 4x - 16

Make y the subject of the formula

y = 4x - 16 + 32

y = 4x + 16

Therefore, the equation of the line is

y = 4x + 16