Answer: 0.67 moles
Step-by-step explanation:
6 Li(s) + N2(g) ---> 2 Li3N(s)
The balanced reaction above shows that 6 moles of Lithium, (Li) added to 1 mole of Nitrogen gas, (N2) yields 2 moles of Lithium nitrite, (Li3N)
I.e 1 mole of N2 = 2 moles of Li3N
Since the number of N2 needed to make 1.34 moles of Li3N is unknown, it is represented by Y
So, 1 mole of N2 = 2 moles of Li3N
Y = 1.34 moles of Li3N
To get the value of Y, cross multiply
1.34 x 1 = Y x 2
1.34 = 2Y
To get the value of Y divide both sides by 2
1.34/2 = 2Y/2
0.67 = Y
Thus, 0.67 moles of N2 is needed to make 1.34 moles of Li3N.