Answer:
it stays the same until t=0, where it is undefined
Explanation:
2t/t = 2 . . . . when t ≠ 0
2t/t = undefined when t = 0.
The value of t can increase or decrease and the value of the ratio remains the same. The value has a "hole" at t=0, where it is undefined. Otherwise, its value is always 2.