Answer:
After 20 months
Explanation:
This is a compound growth problem which has the formula:
![F=P(1+r)^t](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rmj7b2upt2w21bnc516zo95gfwrkj516lf.png)
Where
F is future value
P is present amount
r is the rate of growth
t is the time (in months)
Future amount is $65, what he needs at-least
P is the initial amount, that is $10
r is the rate of growth, which is 10% or 10/100 = 0.1
t is time in months, what we need to find
Substituting and solving we get:
![F=P(1+r)^t\\65=10(1+0.1)^t\\65=10(1.1)^t\\6.5=1.1^t\\ln(6.5)=ln(1.1^t)\\ln(6.5)=t*ln(1.1)\\t=(ln(6.5))/(ln(1.1))\\t=19.64](https://img.qammunity.org/2021/formulas/mathematics/high-school/zvhbtirvvtfk3d0ze8n0tg6yfzslkch0fr.png)
He would need 19.64 months to save up at-least 65. So, that means, he would need 20 months