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Find the value of x in the isosceles triangle shown


Find the value of x in the isosceles triangle shown ​-example-1
User Donnette
by
7.9k points

2 Answers

5 votes

Answer:

Option 4

Explanation:

sqrt(3² + 2²)

sqrt(9+4)

sqrt(13)

User Jknotek
by
8.3k points
6 votes

Answer:

x =
√(13)

Explanation:

The line from the vertex to the base is a perpendicular bisector and divides the triangle into 2 right triangles.

Consider the right triangle on the left with base 2

Using Pythagoras' identity

The square on the hypotenuse (x) is equal to the sum of the squares on the other 2 sides, that is

x² = 2² + 3² = 4 + 9 = 13 ( take the square root of both sides )

x =
√(13)

User Georgiana
by
7.4k points

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