Question

Kevin and Randy Muise have a jar containing 83 coins, all of which are either quarters or nickels. The total value of the coins in the jar is $13.95. How many of each type of coin do they have?

The jar has how many quarters and how many nickels ?

Answer 1

A) N + Q = 83

B) .05N + .25Q = 13.95

We multiply B) by -20

B) -N - 5Q = -279.00 then add it to A)

A) N + Q = 83

4 Q = 196

There are 49 quarters and

34 nickels

CHECK:

49 * .25 = 12.25 and 34 * .05 = 1.70

12.25 + 1.70 = 13.95

Solution is correct

Explanation:

Answer 2

34 Nickles 49 Quarters

Explanation:

You have to give variables to the Quarters and Nickles (x and y)

Then you have to write corresponding equations based on the problem:

x+y=83

.25x+.05y=13.95

Then you would solve for y by isolating the x value in the first equation and plugging it into the second equation.

x=83-y ----> .25(83-y)+.05y=13.95

Solve for y

y=34

Then plug y into first equation to get quarters