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The bottle of Wang resin you have been provided with indicates the quantity of surface linker to be 0.75 mmol/g. The bottle contains 675mg resin, and you use the remainder in your synthesis. How many mmol linkers are present on this mass of resin

User Jan Petr
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1 Answer

1 vote

Answer:


n_(linerks)=0.506mmol

Step-by-step explanation:

In this case, a mole-mass relationship is enough to compute the amount in mmol of the linkers that are present on such mass of resin as shown below:


n_(linerks)=675mg*(1g)/(1000mg)*(0.75mmol)/(1g) \\n_(linerks)=0.506mmol

Best regards.

User Uelordi
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