Answer: (x+11)(2x-1)
Explanation:
First, you want to look at the quadratic. Clearly it doesn't have any GCF. So what you have to do is multiply 2 to the c value: -11. To get:
![x^(2) +21x-22](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lrv5i6kewgjfy7mvn5u3otl2it4gjei5e5.png)
Second, you find the factors of -22 that add to 21.
I've isolated the factors to be 22 and -1. So like a regular quadratic you solve and "plug" it in. (x+22)(x-1)
Third, you can't forget about the multiplied 2. You have to distribute it by plugging the 2 back in front of x in both parenthesis groups. (2x+22)(2x-1)
As you can see, 2x+22 can be simplified. so you simplify, and you get(x+11)(2x-1).