Final answer:
When crossing a homozygous two-horned zork (YY) with a heterozygous two-horned zork (Yy), the genotypes of the possible offspring are homozygous dominant (YY) or heterozygous (Yy), with a predicted genotypic ratio of 1:1.
Step-by-step explanation:
Crossing a Homozygous Two-Horned Zork with a Heterozygous Two-Horned Zork
When crossing a homozygous two-horned zork (let's assume the homozygous genotype is YY) with a heterozygous two-horned zork (Yy), we can predict the possible genotypes of their offspring using a Punnett square. The homozygous parent can only pass on the Y allele, while the heterozygous parent can pass on either the Y or y allele, giving us two possible combinations for the offspring's genotype: YY (homozygous dominant) or Yy (heterozygous).
Using a Punnett square:
The top row represents the alleles from the homozygous parent (YY).
The side column represents the alleles from the heterozygous parent (Yy).
The Punnett square would look like this:
Row 1: Y from homozygous parent, Y from heterozygous parent (YY)
Row 2: Y from homozygous parent, y from heterozygous parent (Yy)
There are two possible offspring genotypes:
YY (homozygous dominant)
Yy (heterozygous)
Thus, the offspring can either be homozygous dominant or heterozygous with a genotypic ratio of 1:1.