Question

Point P' is the image of P(6,0) under the translation

(x,y) → (x – 6, y - 1).
What are the coordinates of P'?

Answer 1

Explanation:

Answer 2

P' = (0, -1)

Explanation:

Step 1: Send point P through the translation

P' = (x - 6, y - 1)

P' = ((6) - 6, (0) - 1)

P' = (0, -1)

Answer: P' = (0, -1)