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(7^2)^4= n^8 solve for n
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5 votes
(7^2)^4= n^8 solve for n

User Anika
by
8.9k points

2 Answers

2 votes

Answer:

7 :)

Explanation:

User Daniel Morris
by
8.2k points
5 votes

Answer:

n=7

Explanation:

(7^2)^4= n^8

We know that a^b^c = a^(b*c)

7^(2*4) = n^8

7^8 = n^8

Since the exponents are the same, the bases must be the same

n=7

User Moshez
by
6.8k points
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