Answer:
T-= T∞= 15 Degree Centigrade
Step-by-step explanation:
Temper distribution inside the slab:
T- T∞/Ti- T∞ = e r f (x / 2√α t)
T-15/325-15 = e r f (45 *10^-3 / 2√5.6*10^-6*3*60
z e r f (z)
0.70 0.6768
0.75 0.7112
hence , e r f (0.7087) = 0.6828.
T-15 =310 (0.6828)
T= 226.67 Degree centigrade (This is temperature at the depth of 45 mm after 3 min.
Temperature at surface = T = T∞= 15 Degree Centigrade.