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A function is shown f(x)=5(x-2)^2+3 what is the minimum value of the function

User Lukess
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1 Answer

3 votes

Answer:

+ 3

Explanation:

The equation of a parabola in vertex form is

f(x) = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

f(x) = (x - 2)² + 3 ← is in vertex form

with vertex = (2, 3)

The minimum value occurs at the vertex and is the value of k

k = 3, thus minimum value is 3

User Aditya Kapoor
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