Question

Calculate the solubility of ( = ) in moles per liter. Ignore any acid–base properties. s = mol/L Calculate the solubility of ( = ) in moles per liter. Ignore any acid–base properties. s = mol/L Calculate the solubility of ( = ) in moles per liter. Ignore any acid–base properties. s = mol/L

Answer 1

This is an incomplete question, here is a complete question.

Calculate the solubility of each of the following compounds in moles per liter. Ignore any acid-base properties.

CaCO₃, Ksp = 8.7 × 10⁻⁹

Answer : The solubility of CaCO₃ is,
`9.33* 10^(-5)mol/L`

Explanation :

As we know that CaCO₃ dissociates to give
`Ca^(2+)` ion and
`CO_3^(2-)` ion.

The solubility equilibrium reaction will be:

`CaCO_3\rightleftharpoons Ca^(2+)+CO_3^(2-)`

The expression for solubility constant for this reaction will be,

`K_(sp)=[Ca^(2+)][CO_3^(2-)]`

Let solubility of CaCO₃ be, 's'

`K_(sp)=(s)* (s)`

`K_(sp)=s^2`

`8.7* 10^(-9)=s^2`

`s=9.33* 10^(-5)mol/L`

Therefore, the solubility of CaCO₃ is,
`9.33* 10^(-5)mol/L`