Question

1. Lisa sold tickets for a local play. Children's tickets cost $4 each and adult tickets cost $6 each. If 383 tickets were sold for a total of $2034, how many of each type of ticket were sold?

Answer 1

Answer:132 children's tickets and 251 adult tickets were sold.

Step-by-step explanation: x will equal children's tickets and y will equal adult tickets sold (x + y = 383) since children's tickets are four dollars and adult tickets are six dollars it would then be (4x + 6y = 2034, since that was the total amount) Substituting x = 383 - y into equation 1, it becomes

4(383 - y) + 6y = 2034 (solve from there)

Answer 2

Answer: 132 children's tickets and 251 adult tickets were sold.

Explanation:

Let x represent the number of children tickets that were sold.

Let y represent the number of adult tickets that were sold.

A total number of 383 tickets were sold. This means that

x + y = 383

Children's tickets cost $4 each and adult tickets cost $6 each. If the total amount for which the tickets were sold is $2034, it means that

4x + 6y = 2034 - - - - - - - - -- -1

Substituting x = 383 - y into equation 1, it becomes

4(383 - y) + 6y = 2034

1532 - 4y + 6y = 2034

- 4y + 6y = 2034 - 1532

2y = 502

y = 502/2

y = 251

x = 383 - y = 383 - 251

x = 132