Question

What is the width of todors area model?
10x exponent2 -5x 15

Answer 1

The width of the area model is equal to

`(2x^2-x+3)\ units`

Explanation:

The complete question is

Todor was trying to factor 10x^2-5x+15 he found the greatest common factor of these terms was 5 what is the width

we know that

The area of a rectangular model is given by the formula

`A=LW` ----> equation A

where

L is the length

W is the width

we have

`A=10x^2-5x+15`

Factor the expression

`A=5(2x^2-x+3)`

substitute the value of the Area in the equation A

`5(2x^2-x+3)=LW`

In this problem

The greatest common factor of these terms is the length (L=5 units)

so

we can say that the width is equal to (2x^2-x+3)

therefore

The width of the area model is equal to

`(2x^2-x+3)\ units`