Question

How would you expand log412 so that it can be evaluated, given log43 ≈ 0.792? Log Subscript 4 Baseline 3 times log Subscript 4 Baseline 4 StartRoot a squared + b squared EndRoot log 3 + log 4 log Subscript 4 Baseline 3 + log Subscript 4 Baseline 4 log 3 times log 4

Answer 1

Answer: log412 = 1.792

Explanation:

log412 = log4(3 x 4)

log4(3 x 4) = log4(3) + log4(4)

log4(4) = 1

log4(3) = .792

1 + .792 = 1.792

log412 = 1.792