Question

Find the vertex for the function:
y = 6(x + 3)^2 - 1

Answer 1

The vertex would be (-3, -1)

Explanation:

Since this is in vertex form already, a(x-h)^2+k where h is the x value of the vetex, and k is y.

We would take the opposite of +3 and get -3, which gives us our x cordinate.

We don't change the k value, so it just stays -1, giving us our y value.

Therefore, the vertex is at (-3, -1)

Hope this helps!