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A new car that is a gas- and electric-powered hybrid has recently hit the market. The distance travelled on 1 gallon of fuel is normally distributed with a mean of 45 miles and a standard deviation of 8 miles. Find the probability of the following events: A. The car travels more than 53 miles per gallon. Probability

User Nickgrim
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1 Answer

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Answer:

15.87% probability that the car travels more than 53 miles per gallon.

Explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean
\mu and standard deviation
\sigma, the zscore of a measure X is given by:


Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:


\mu = 45, \sigma = 8

Find the probability of the following events: A. The car travels more than 53 miles per gallon. Probability

This is the pvalue of Z when X = 53. So


Z = (X - \mu)/(\sigma)


Z = (53 - 45)/(8)


Z = 1


Z = 1 has a pvalue of 0.8413

1 - 0.8413 = 0.1587

15.87% probability that the car travels more than 53 miles per gallon.

User Withtaker
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