Answer:
161.3 kg of NH₄HCO₃ are produced
Step-by-step explanation:
Firstly we need to determine the reaction by the reactants and the formed products. The equation will be:
CO₂ + NH₃ + H₂O → NH₄HCO₃
Let's determine the moles of ammonia that has reacted, at STP
STP = 1 atm, 273K
We apply the Ideal Gases Law → P . V = n . R . T → P . V/ R. T = n
1 atm . 4575L / 0.082 . 273 = n → 204.3 moles
As ratio is 1:1, 204.3 moles of ammonia will produce 204.3 moles of NH₄HCO₃ . Let's convert the moles to mass:
204.3 mol . 79g / 1 mol = 16139.7 g
We convert the mass from g to kg → 16139.7 g . 1kg / 1000g = 161.3kg