Question

(-5m^2-8) -(-3m^2+m+2)=(−5m 2 −8)−(−3m 2 +m+2)

Answer 1

m = 0, 2.

Explanation:

(-5m^2-8) -(-3m^2+m+2)=(−5m *2 −8)−(−3m* 2 +m+2)

= -5m^2 - 8 + 3m^2 - m - 2 = -10m - 8 + 6m - m - 2

= -2m^2 + 4m = 0

2m( -m + 2) = 0

m = 0, 2.

Answer 2

m = 2 or m = 0

Explanation:

Solve for m over the real numbers:

(-5 m^2 - 8) - (-3 m^2 + m + 2) = (-5 2 m - 8) - (m - 3 2 m + 2)

(-5 m^2 - 8) - (-3 m^2 + m + 2) = -2 m^2 - m - 10 and (-5 m 2 - 8) - (m - 3 m 2 + 2) = -5 m - 10:

-2 m^2 - m - 10 = -5 m - 10

Add 5 m + 10 to both sides:

4 m - 2 m^2 = 0

Factor m and constant terms from the left hand side:

-2 m (m - 2) = 0

Divide both sides by -2:

m (m - 2) = 0

Split into two equations:

m - 2 = 0 or m = 0

Add 2 to both sides:

Answer: m = 2 or m = 0