Question

A grocer wants to mix nuts costing 5.00 per kilogram with nuts costing 8.00 per kilogram to make a 10 kilogram mixture for 6.00 a kilogram. How much of each type should he mix.

Answer 1

mix nuts 20/3

nuts 10/3=

Explanation:

x+y=10

5x+8y=60

Answer 2

Explanation:

let E be weight of expensive nuts, C be cheaper nuts

E*8+C*5=10*6 value equation

E+C=10 mass equation

Solve it by any method, I will do determinants

Det: 8-5=3

E= (60-50)/3=10/3 =3.33 lb

C= 80-60 /3=20/3 =6.66 lb