Question

A plug-in transformer supplies 9 V to a video game system. (a) How many turns are in its secondary coil, if its input voltage is 111 V and the primary coil has 340 turns? g

Answer 1

28 turns

Step-by-step explanation:

The transformer equation given as

`(V_(s) )/(V_(p) ) =(N_(s) )/(N_(p) )`

Here,
`{N_(s) }, {N_(p) }` are the number of loops in the primary and secondary coil respectively and
`{V_(s) },{V_(p) }` are the output and input voltages.

Substitute the given values, we get

`(9.00V)/(111.00V) =(N_(s) )/(340)`

`N_(s) =(9*340 )/(111)`

`N_(s)=27.57 =28`

Thus, the turns in secondary coil are 28.

Answer 2

The number of turns in the secondary coil is 28.

Step-by-step explanation:

Given that,

Input voltage given to the transformer,
`V_p=111\ V`

Output voltage supplied to the video game,
`V_s=9\ V`

Number of turns in the primary coil,
`N_p=340`

We need to find the number of turns in its secondary coil. We know that the transformer equation is given by :

`(V_s)/(V_p)=(N_s)/(N_p)\\\\N_s=(V_s)/(V_p)* N_p\\\\N_s=(9)/(111)* 340\\\\N_s=27.56`

or

`N_s=28`

So, the number of turns in the secondary coil is 28.