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A neighborhood transformer on the top of a utility pole transforms 19.0 kV 60.0 Hz alternating voltage down to 120.0 V to be used inside a house. If the secondary coil of the transformer has 159.0 turns, then how many turns does the primary coil have?

1 Answer

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Answer:

Step-by-step explanation:

Following relation exists between number of turns and volt

Volt in primary / volt in secondary = no of turns in primary / no of turns in sec

19000 / 120 = no of turns in primary / 159

no of turns in primary = 19000 x 159 / 120

= 25175 Ans .

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