Answer:
![2√(26)\text{ cm}, 2√(6)\text{ cm}](https://img.qammunity.org/2021/formulas/mathematics/high-school/xszbtb4whotha46d862n6z1631mfj0vpu9.png)
Explanation:
We are given the following in the question:
Two sides of triangle:
8 cm and
cm
Let the third side be x cm.
Pythagoras theorem:
The sum of square of two sides of a right angled triangle is equal to the square of hypotenuse.
If the third side is hypotenuse, then by Pythagoras theorem:
![x^2 = 8^2+(√(40))^2\\x^2 = 64 + 40\\x^2 = 104\\x = √(104)=2√(26)\text{ cm}](https://img.qammunity.org/2021/formulas/mathematics/high-school/46ri1omuk7o97vkqpss53du74mmqw2a2vz.png)
If the third side is not hypotenuse, then
![8^2 = x^2 + (√(40))^2\\64 = x^2 + 40\\x^2 = 24\\x = √(24) = 2√(6)\text{ cm}](https://img.qammunity.org/2021/formulas/mathematics/high-school/5cdj0iti31cf4mgudri1b9nj0vpgsd9se2.png)
Thus, possible third side of triangle are
![2√(26)\text{ cm}, 2√(6)\text{ cm}](https://img.qammunity.org/2021/formulas/mathematics/high-school/xszbtb4whotha46d862n6z1631mfj0vpu9.png)